TY - JOUR AB - Solution by N. P. Pandya, Amreli (Kathiawad), India. Let P be the given point, (h, k); QL (y == 1) the given line; x2^-y2 == a3 the given circle; PQFG (y == mx+c) the required line with PQ == FG. PL(=p)–QL. The ordinates of F and G are the values of y given by the solution of ^., == of the 0 == p(l4-/^) == 2^V^2(l+^2)-c2. This equation gives m; and since P (h, k) lies on y gives, c. .\ ?/ = P^.T’ 4-^-^ determined. .-. P______ = ma;4-c, fc == hm-f-c A solution to 612 tuns Late Solution. received from G. C. Williams. PROBLEMS FOR SOLUTION. Proposed by Walter Warne, State College, Pa. Obtain all the values of x and y in the equations x-\-y = 14 y2, x^-^-xy^+xy2 == 600-a;2?/4~2a:22/3 637. Proposed by A. Pelletier, Ecole Polytechnique, Montreal, Can. A, B, C are three numbers having, respectively,